TUTTEE ACADEMY LOGO
broken image
  • Home
  • About Us
  • Subjects 
    • CHEMISTRY
    • BIOLOGY
    • PHYSICS
    • MATHEMATICS
    • PSYCHOLOGY
    • ECONOMICS
    • BUSINESS
    • COMPUTER SCIENCE
    • CHINESE
    • ENGLISH
    • SPANISH
    • IBDP IA / EE
    • IBDP TOK
    • ONLINE TUTORIAL
  • Exam Boards 
    • IBDP
    • IBMYP
    • IGCSE & GCSE
    • HKDSE
    • GCE A-LEVELS
  • Courses 
    • IBDP Tuition
    • GCE A-Level Tuition
    • IBMYP Tuition
    • I/GCSE Tuition
    • HKDSE Tuition
  • Admission Test Prep 
    • PREDICTED GRADE
    • SAT / SSAT
    • UKISET (UK)
    • BMAT
    • UKCAT / UCAT
    • LNAT
    • TMUA (Cambridge)
  • Student Results 
    • IBDP STUDENT RESULTS
    • IGCSE & GCSE MATHEMATICS
    • A-LEVEL STUDENT RESULTS
    • IGCSE STUDENT RESULTS
    • GCSE STUDENT RESULTS (UK)
    • HKDSE STUDENT RESULTS
    • OUR STORIES
  • Question Bank
  • Resources
SCHEDULE A LESSON NOW

PHYS - Scientific Method

Physics, scientific method - IBDP | DSE | GCE | IAL | AP Physics

· physics,scientific method

In IGCSE Physics, you should be able to conduct simple experiments and interpret the results scientifically. 

Let's take a look at some examples!! 😄

A student measures the circumference of a circular pipe. He wraps a length of string around the pipe five times and marks it with ink, as shown in the photograph.

broken image

(a) The student unwraps the string and holds it against a ruler with a centimeter scale. The next photograph shows the first two ink marks on the string.

broken image

(i) Estimate the circumference of the pipe, using the photograph of the string and the centimeter scale. Give your answer to two significant figures.

→ Because the student left marks for every wrap around the pipe, the distance between the two marks is approximately the circumference of the pipe.

→ 47.3 - 41.9 = 5.4 cm

(ii) The student finds that the total length of string for 5 turns is 25.6 cm. Calculate the average (mean) circumference of the pipe using this value.

→ 5 turns means 5 circumferences.

→ average circumference = 25.6 / 5 = 5.12 cm

(iii) The student measures the diameter of the pipe using a digital caliper.

broken image

The caliper shows that the diameter is 15.10 mm. Calculate the circumference of the pipe using the formula circumference = diameter × π

→ circumference = 15.10 x π = 47.44 mm = 4.744 cm

(b) The student uses two methods to find the circumference

  • averaging, using a measured length of string
  • calculating, using the digital caliper reading 

Explain why the two methods are likely to give different results.

Possible answers:

- The equation to calculate the circumference of the pipe is valid only for circles; the pipe may not be perfectly circular.

- The width of the pen mark may affect the readings.

- There may be parallax error when using the ruler; the readings may be different when viewed from different angles.

- The caliper may not be properly calibrated and give results with errors.

- Caliper and ruler have different precision.

- The caliper may not have been placed at right angles.

- The thickness of the string will make the diameter bigger.

- The string may have stretched during the experiment.

Wanna Boost Up Your IGCSE Physics?

SIGN UP FOR A FREE TRIAL NOW
Subscribe
Previous
PHYS - Motion in the Universe
Next
PHYS - Energy Resources
 Return to site
Profile picture
Cancel
Cookie Use
We use cookies to improve browsing experience, security, and data collection. By accepting, you agree to the use of cookies for advertising and analytics. You can change your cookie settings at any time. Learn More
Accept all
Settings
Decline All
Cookie Settings
Necessary Cookies
These cookies enable core functionality such as security, network management, and accessibility. These cookies can’t be switched off.
Analytics Cookies
These cookies help us better understand how visitors interact with our website and help us discover errors.
Preferences Cookies
These cookies allow the website to remember choices you've made to provide enhanced functionality and personalization.
Save