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PHYS - Distance-time and Velocity-time Graphs

Physics, motion, distance-time graphs, velocity-time graphs - IBDP | GCE | AL | HKDSE | AP Physics

· physics,motion,graphs

**1. Distance-time graph**

**Points to remember:**

**average speed = distance moved / time taken**- The
**slope**of the distance-time graph represents the average**speed**of travel. The steeper the graph, the faster the travel. - A horizontal line means the object is not moving.

Let's take a look at an example of a graph showing the distance moved by a toy car!

**Section A**: It took 20 seconds for the toy car to travel 1m. The**average speed**is 1m/20s=**0.05m/s**.**Section B**: The toy car stayed**stationary**for 10 seconds.**Section C**: It took 5 seconds for the toy car to travel 2m. The**average speed**is 2m/5s=**0.4m/s**.**Section D**: The toy car stayed**stationary**for 10 seconds.

The car traveled **fastest** during section **C**.

**2. Velocity-time graph**

**Points to remember:**

**acceleration = change in velocity / time taken**- The
**slope**of the velocity-time graph represents the**acceleration**. - The
**area**below the velocity-time graph is equal to the**distance**traveled.

Let’s take a look at an example of a graph showing the velocity of a car!

**Section A**: The car was stationary initially but accelerated to 20m/s for 10 seconds. The**acceleration**is (20m/s - 0m/s) / 10s =**2m/s**.The^{2}**distance travelled**during section A is 0.5 x 10s x 20m/s =**100m**.**Section B**: The car ran at a**constant velocity**of 20m/s for 20 seconds. There was no acceleration. The**distance travelled**during section B is 20s x 20m/s =**400m**.**Section C**: The car decelerates gradually from 20m/s to a stop for 40 seconds. The**acceleration**is (0m/s - 20m/s) / 40s =**-0.5m/s**. The^{2}**distance travelled**during section C is 0.5 x 40s x 20m/s =**400m**.

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