CHEM - Faraday and Mole Calculation Example 1
Chemistry, Faraday, Mole Calculations - IGCSE | AP Chemistry
When dealing with questions related to mole calculations, following a few simple steps can make it easier to solve them. 🤔
🤓Here is an example:
Start by writing out the equation
Cu2+ + 2e > Cu
Find out the coulombs of electrons flowing
Charge (coulomb, C) = Current (ampere, A) × Time (second, s).
*Remember to convert the time into seconds !
Therefore, Charge = 0.2 × 7200 = 1440 coulombs
Convert Coulombs into moles of electrons
Moles = Coulombs / faraday
Moles = 1440/96500 = 0.015
Find the moles of the product using the scale factor
*From the equation, for every 2 moles of electrons, there will be 1 copper.
Scale factor = moles of product/moles of electrons = 1/2
Thus, there are 0.015 × 1/2 = 0.0075 moles of Cu
Convert moles into mass
Mass = Moles × Molar Mass
The mass of Cu = 0.0075 × 63.5 = 0.48 g
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