CHEM - Faraday and Mole Calculation Example 2
Chemistry, Faraday, mole calculations- IBID | DSE | GCE | IAL | AP Chemistry
Here is another example of mole calculation🧐
Start by writing down the equation
2Cl- > Cl2 + 2e-
Find the number of moles in the 18 cm3 of chlorine gas
Volume = Moles × Molar Volume
❗️❗️ Remember to use the same units (cm3)
By rearranging the above equation,
Moles = 18 cm3 / 24000 cm3 = 0.00075 moles
Note that electricity always refers to the flow of electrons
From the half equation, 2 electrons are needed to produce chlorine gas
Hence, 2e- = 96500 × 2 = 193000 C
Don't forget about the moles!
Multiply the number of coulombs by the amount of moles calculated earlier
193000 × 0.00075 = 144.75 Coulombs
Therefore, 144.75 Coulombs are required to produce 18 cm3 of chlorine gas
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