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AS/A-Level Chemistry- Enthalpy(iii) applications

calculations and possible questions

· enthalpy,question analysis,A-level Chemistry,Calculations,thermodynamics

Measuring Enthalpy Changes

Calorimetry

  • involves the practical determination of enthalpy changes
  • usually involves heating (or cooling) known amounts of water

🔥water is heated up: reaction is EXOTHERMIC

❄️water cools down: reaction is ENDOTHERMIC

Calculation

The energy required to change the temperature of a substance can be found as:

q = m  x  c  x  ∆Τ

where    q=heat energy(kJ);      m=mass(kg);      c=Specific Heat Capacity (kJ K -1 kg -1) [ water is 4.18 ];                                                              ∆Τ=change in temperature(K)

Graphical method

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  • The  temperature is taken every half minute before mixing the reactants.
  • Reactants are mixed after 3 minutes.
  • Further readings are taken every halfminute as the reaction mixture cools.
  • Extrapolate the lines as shown and calculate the value of ∆Τ.

Example (calculating enthalpy change with given data):

225cm3 of 2.0M HCl was added to 25cm3 of 2.0M NaOH in an insulated beaker.The initial temperature of both solutions was 20°C.  The reaction mixture wasstirred to ensure mixing and the highest temperature reached by the solution was 33°C.  Calculate the Molar Enthalpy of Neutralisation.

  • Temperature rise (∆Τ) =    306K - 293K=    13K
  • Volume of resulting solution=    50cm3=    0.05 dm3
  • Equivalent mass of water=    50g=    0.05 kg

Heat absorbed by the water (q)=    0.05  x   4.18  x  13=   2.717 kJ

Moles of HCl reacting=    2   x    25/1000=    0.05 mol

Moles of NaOH reacting=    2   x    25/1000=    0.05 mol

Equation:     NaOH    +    HCl    ——>    NaCl    +    H2O

Moles of water produced=    0.05 mol

Enthalpy change per mol  (∆Η)=  − ( heat energy / moles of water )

=   − 2.717 / 0.05       ANS: − 54.34 kJ mol -1

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Example (relating enthalpy of dissociation to bonding) in A-Level Chemistry:

Explain why the enthalpy of lattice dissociation of CaF2is greater than the enthalpy of lattice dissociation of CaCl2and why the enthalpy of lattice dissociation of CaO is greater than the enthalpy of lattice dissociation of BaO.

  • F-ion has a smaller size, greater charge densitythan Cl-ion.
  • Stronger electrostatic forces of attraction between oppositely-charged ions, F-and Ca2+ions, stronger ionic bonds between oppositely-charged ions, F-and Ca2+ions.
  • More energy required to break the stronger ionic bonds between oppositely-charged ions, F-and Ca2+ions.
  • Ca2+ion has a smaller size, greater charge density than Ba2+ion.
  • Stronger electrostatic forces of attraction between oppositely-charged ions, Ca2+and O2-ions, stronger ionic bonds between oppositely-charged ions, Ca2+and O2-ions.
  • More energy required to break the stronger ionic bonds between oppositely-charged ions,Ca2+and O2-ions.

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Drafted by Eunice Wong (Chemistry)

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