TUTTEE ACADEMY LOGO
broken image
  • Home
  • About Us
  • Subjects 
    • CHEMISTRY
    • BIOLOGY
    • PHYSICS
    • MATHEMATICS
    • PSYCHOLOGY
    • ECONOMICS
    • BUSINESS
    • COMPUTER SCIENCE
    • CHINESE
    • ENGLISH
    • SPANISH
    • IBDP IA / EE
    • IBDP TOK
    • ONLINE TUTORIAL
  • Exam Boards 
    • IBDP
    • IBMYP
    • IGCSE & GCSE
    • HKDSE
    • GCE A-LEVELS
  • Courses 
    • IBDP Tuition
    • GCE A-Level Tuition
    • IBMYP Tuition
    • I/GCSE Tuition
    • HKDSE Tuition
  • Admission Test Prep 
    • PREDICTED GRADE
    • SAT / SSAT
    • UKISET (UK)
    • BMAT
    • UKCAT / UCAT
    • LNAT
    • TMUA (Cambridge)
  • Student Results 
    • IBDP STUDENT RESULTS
    • IGCSE & GCSE MATHEMATICS
    • A-LEVEL STUDENT RESULTS
    • IGCSE STUDENT RESULTS
    • GCSE STUDENT RESULTS (UK)
    • HKDSE STUDENT RESULTS
    • OUR STORIES
  • Question Bank
  • Resources
SCHEDULE A LESSON NOW

I/GCSE Mathematics Question Analysis - Mathematics - Short Questions

I/GCSE Mathematics Question Analysis

· IGCSE Mathematics,Quadratic Formula,natural number

I/GCSE Mathematics Question Analysis Topic: Mathematics - Short Questions

Exam Questions:

1) Find the values (s) of k so that the quadratic equation 3x2 − 2kx + 12 = 0 has equal roots.

2) The sum of first 20 odd natural number is..?

Answers:

For I/GCSE Mathematics, you should know:

1) First, let's compare the given quadratic equation with the general quadratic equation of ax2 + bx + c = 0.

In doing so, we obtain the following values:
a = 3, b = -2k, c = 12.

The discriminant (D) of the given quadratic equation would be:
D = b
2 - 4ac
= (-2k)
2 - 4 x 3 x 12
=
4k2 - 144.

For equal roots, the discriminant should equal to 0.

D = 0
4k
2 - 144 = 0
4(k
2 - 36) = 0
k
2 = 36
k = +-6.

As such, the values of the given quadratic equation will have equal roots 6 and -6.

2) In the first 20 odd natural numbers:

The first term, a, is equal to 1.

The common difference, d, is equal to 2.

So, the sum of the first n terms is n/2[2a + (n - 1)d]

From this, we find that n = 20, a = 1 and d = 2.

Substituting these in, we get the sum of the first 20 natuarl numbers: 20/2[2(1) + (20 - 1)2]
= 10 x (2 + 19 x 2) = 10 x 40 =
400.

Work hard for your I/GCSE Mathematics examination!

End of analysis. Great!

broken image

 

CLICK HERE TO LEARN MORE ABOUT OUR I/GCSE MATHEMATICS COURSES!

SIGN UP FOR AN I/GCSE MATHEMATICS TUTORIAL NOW WITH OUR EXPERT TUTORS!

 

Subscribe
Previous
I/GCSE Chemistry Question Analysis - Chemistry - Short...
Next
I/GCSE Biology Question Analysis - Biology - Short Questions
 Return to site
Profile picture
Cancel
Cookie Use
We use cookies to improve browsing experience, security, and data collection. By accepting, you agree to the use of cookies for advertising and analytics. You can change your cookie settings at any time. Learn More
Accept all
Settings
Decline All
Cookie Settings
Necessary Cookies
These cookies enable core functionality such as security, network management, and accessibility. These cookies can’t be switched off.
Analytics Cookies
These cookies help us better understand how visitors interact with our website and help us discover errors.
Preferences Cookies
These cookies allow the website to remember choices you've made to provide enhanced functionality and personalization.
Save