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Mole Calculation
Let's practice mole calculation according to the I/GCSE chemistry curriculum!
There are 6.02 x 10^23 hydrogen atoms in a gram.
6.02 x 10^23 per mole = Avogardo's constant.
Number of atoms in 12g of C-12 is also 6.02 x 10^23 atoms. This is the standard.
For example, for Helium we need 4g to make 1 mole. So 8g of Helium would be 2 moles, which would be 2x(6.02 x 10^23) = 1.2 x 10^24.
If there were 12g of Helium, how many atoms are present in I/GCSE chemistry?
12g of He = 3 moles = 3x(6.02 x 10^3) = 1.8 x 10^25
How many grams are needed for 1 mole? 27g.
2.7g of al = 0.1 ml = 6 x 10^22 Al Atoms
13.5g of al = 0.5 mol = 3 x 10^23
End of this topic!
