·

Mole Calculation

Let's practice mole calculation according to the I/GCSE chemistry curriculum!

There are 6.02 x 10^23 hydrogen atoms in a gram.**6.02 x 10^23 per mole = Avogardo's constant**.

Number of atoms in 12g of C-12 is also 6.02 x 10^23 atoms. This is the **standard**.

For example, for Helium we need 4g to make 1 mole. So 8g of Helium would be 2 moles, which would be 2x(6.02 x 10^23) = 1.2 x 10^24.

If there were 12g of Helium, how many atoms are present in I/GCSE chemistry?

12g of He = 3 moles = **3x(6.02 x 10^3)** = 1.8 x 10^25

How many grams are needed for 1 mole? **27g**.

2.7g of al = 0.1 ml = **6 x 10^22 Al Atoms**

13.5g of al = 0.5 mol = 3 x 10^23

End of this topic!