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BMAT Prep - Physics Paper - Q171 & Q245

BMAT Physics

· bmat,physics

BMAT Prep Question Analysis - Q171 & Q245

Q171 Zn and Cu² undergo an equimolar redox reaction, whereby Zn2+ is formed. After the reaction, what is the oxidation number of Cu?

a. 1

b. 0

c. -1

d. 2

e. -2

Q245 In the figure below, the square ABCD and the triangular region ACE each have area 36.

broken image

Which is the perimeter of the triangle ACD?

broken image

Answer and Explanation

Q171 Answer: b. 0

Explanation: This equimolar redox (reduction-oxidation) reaction, 2 electrons are traded between these two metals. Since zinc loses 2 electrons, that must mean that Cu?* gains 2 electrons in the reaction and forms an uncharged Cu atom. The oxidation number of a monoatomic species is equal to its net charge (zero in this case)

Q245 Answer: b. 12 + 6√2 

Explanation: Since the area of square ABCD is 36, we deduce that each side of the square measures √36 = 6. We fherefore now know that AD = CD = 6.

The distance AC is calculated using the Pythagorean theorem and is equal to √(36 + 36) i.e. √72 or 6√2.

Thus the perimeter of the triangle ACD is 6+6+6√2 = 12+ 62. Note that the information given about ACE is not needed to solve this question.

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Drafted by Quincy (BMAT Prep)

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