**Example 1**

How does a displacement time graph show that its **oscillations are not damped** in IB physics curriculum?

**Answer**

The amplitude **remains constant**

**Example 2**

Calculate the **magnitude** of the maximum acceleration when the time period is 0.2s and the maximum displacement is 0.02m.

**Answer**

Use the equation **a=-ω^2 * xo**

**ω=2π/t**

a=(2π/0.2)^2 * 0.02=19.7m/s

**Example 3**

Calculate the **speed** of the oscillation when the time taken is 0.12s to displace by 1.62cm and maximum displacement is 0.02m.

**Answer**

Use the equation **v = (2π/t)√(xo^2-x^2)** Answer

v = (2π/t)√(xo^2-x^2)

v = (2π/0.12)√((0.02)^2-(0.0162^2)

v = 31.4√((0.02)^2-(0.0162^2) = **0.37m/s**

**Example 4**

Following the question above, if the diplacement was in a **negative direction** would be the direction of its motion.

**Answer**

Even though it would seem logical that the motion would also be in the negative direction it is actually positive. This is because if it were displaced by **-0.0162 m**, -0.0162^2 is actually a **positive number**, therefore making the **velocity positive**. As velocity is a vector quantity, if it is positive it shows that the direction of motion is to the **right** in IB physics.

End of this part! Please read next part as well!

Drafted by Gina