When dealing with questions related to percentage yield calculations, it is important to remember the formula👇

🧐**Percentage yield = (Actual yield ÷ ** **Theoretical yield) x 100% **

**Key Points**

**The theoretical yield is the quantity of product predicted from the chemical reaction****The actual yield is usually less than the theoretical yield due to experimental errors such as incomplete reaction or loss of some products.**

**Example 1**🤓

**CaCO _{3} ⇒ CaO + CO_{2}**

**In the above reaction, the expected theoretical yield of CaO obtained from 100g of CaCO _{3} is 56g.**

**However, if the actual yield is only 48g of CaO, what is the percentage yield?**

**Answer:** By substituting the values in the formula,

**Percentage yield= (48**÷**56) x 100% = 86%**

**Example 2**🤓

**In an experiment to displace Copper from Copper Sulfate, 6.5 g of Zinc was added to excess Copper (II) Sulphate Solution. The Copper was filtered off, washed and dried. The mass of Copper obtained was 4.8 g. Calculate the Percentage Yield of Copper.**

**Step 1- Write Down the Equation**

🧐**Zn (s) + CuSO _{4} (aq) → ZnSO_{4} (aq) + Cu (s)**

**Step 2- Calculate the Moles of Zinc **

🧐**Moles = Mass ÷** **Molar Mass**

**Moles of Zinc = 6.5 ÷ 65 = 0.10 Mol**

**Step 3-Find the moles of Copper using the mole ratio**

🧐**According to the equation, 1 mole of zinc requires 1 mole of copper**

**Therefore, moles of Copper = 0.10 mol**

**Step 4- Calculate the mass of the copper by rearranging the equation**

**Mass of Copper= Moles x Molar Mass = 0.10 x 64 =6.4 g**

💪**Final Step-Calculate the Percentage of Yield of Copper**

**Percentage Yield = ( 4.8 ÷ 6.4 ) x 100 = 75%**

**Example 3**🤓

**The percentage yield and theoretical yield of ammonia are 15% and 44.2 tonnes respectively. Find the actual yield of ammonia.**

🧐**Just rearrange the equation to find the actual yield**

**Actual Yield of Ammonia= 44.2 tonnes x 15% = 6.63 tonnes**

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