Before moving onto analyzing some examples, here are few reminders.๐
๐งโThe volume occupied by one mole of a gas is called the molar volume which is 24 dm3 / 24000 cm3
๐งโNumber of moles of gas = Volume of gas / Molar Volume of gas
* Under the same temperature and pressure โ๏ธ โโ
Example 1๐โ
What is the number of moles of methane in 1.44 dm3 of the gas measured at room temperature and pressure?
(Molar Volume of gas at room temperature and pressure= 24 dm3mol-1)
Answer: No of moles of methane= Volume of methane/Molar volume of gas
Therefore, 1.44 dm3 / 24 dm3mol-1 = 0.0600 mol
Yup, keep in mind that for some questions all you need to do is substitute the correct values into the equation.
*Watch out for the units too โ๏ธ โโโ
Example 2๐โ
What is the volume, measured at room temperature and pressure, occupied by 13.2 g of carbon dioxide?
(Relative atomic masses: C=12, O=16; Molar Volume of gas at room temperature and pressure= 24 dm3mol-1 )
Step 1: Find the moles of CO2
๐งโMoles= Mass / Molar Mass
Thus, moles of CO2 = 13.2 g / (12+16+16) = 0.300 mol
๐ชโFinal Step: Rearrange the formula to find the volume of gas
๐ง Volume of CO 2 = Moles of CO2 ร ย Molar Volume of Gas
Volume of CO 2= 0.300 mol ร 24 dm3mol-1 = 7.20 dm3
Example 3๐โโ
Butane burns in oxygen completely to produce carbon dioxide and water according to the following equation:
2C4H10(g) + 13O2(g) โ 8CO2(g) + 10H2O(l)
What volume of oxygen is needed for the complete combustion of butane measured at room temperature and pressure?
(Molar Volume of gas at room temperature and pressure= 24 dm3mol-1= 24000 cm3 mol-1)
Step 1: Find the moles of C4H10 using the formula
Moles of C4H10= Volume of C4H10/ Molar Volume of gas
Hence, 480 cm3/ 24000 cm3mol-1=0.02 mol
Step 2: Use mole ratio to find the moles of O2
๐งโFrom the equation, 2 moles of C4H10 require 13 moles of O2
Moles of O2 = 0.02 ร (13/2) = 0.130 mol
๐ชโLast Step: Rearrange the formula to find the volume of O2
๐ง Volume of O2 = Moles of O2ย ร molar Volume of gas
Volume of O2 = 0.130 mol ร 24 dm3mol-1 = 3.12 dm3
Concept Cleared? Hope you enjoy and give us a "Like" ๐
Got Questions Wanna Ask? Whatsapp Us! We Are Here to Help ๐
TUTTEE ยฉ All Rights Reserved. Unauthorized Copying is prohibited.
Enter Your Email Below ๐ To Keep Yourself Updated on Such Useful Information๐